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Commutative Matrix If A and B are the two square matrices such that AB=BA, then A and B are called commutative matrix or simple commute.
It is not possible to show that since it is not necessarily true.There is absolutely nothing in the information that is given in the question which implies that AB is not invertible.
If, for an n*n matrix, A, there exists a matrix B such that AB = I, where I is the n*n identity matrix, then the matrix B is said to be the inverse of A. In that case, BA = I (in general, with matrices, AB ≠BA) I is an n*n matrix consisting of 1 on the principal diagonal and 0s elsewhere.
If the product of two matrices is an identity matrix then, one matrix is inverse of the other. i.e. AB = I then, A = B-1 and B = A-1Inverse of matrix can be found by using these two results:A = AI and A = IA.By using these results inverse of a matrix can be found by applying same elementary row or column operation on both sides. A on R.H.S. remains as it is.
Explain the Matrix approach to product planning. Suggest a Marketing strategy on the basis of the product evaluation matrix.
It's matrix C.
Cross product tests for parallelism and Dot product tests for perpendicularity. Cross and Dot products are used in applications involving angles between vectors. For example given two vectors A and B; The parallel product is AxB= |AB|sin(AB). If AXB=|AB|sin(AB)=0 then Angle (AB) is an even multiple of 90 degrees. This is considered a parallel condition. Cross product tests for parallelism. The perpendicular product is A.B= -|AB|cos(AB) If A.B = -|AB|cos(AB) = 0 then Angle (AB) is an odd multiple of 90 degrees. This is considered a perpendicular condition. Dot product tests for perpendicular.
Hadamard product for a 3 Γ 3 matrix A with a 3 Γ 3 matrix B
The chemical reaction consists of reactants A and B reacting to form product AB. A and B are the reactants, while AB is the product.
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A matrix with a row or a column of zeros cannot have an inverse.Proof:Let A denote a matrix which has an entire row or column of zeros. If B is any matrix, then AB has an entire rows of zeros, or BA has an entire column of zeros. Thus, neither AB nor BA can be the identity matrix, so A cannot have an inverse, or A cannot be invertible.Since A is not invertible, then Ax = b has not a unique solution.