I think the number that has 8 thousands 6 fewer than thousands 2 fewer than the thousands and four more units than hundreds is 8624.
7252
4117
6,130 has.
3896
The number is 8,413
5483
It is 5305.
To solve this problem, we need to break down the number into its place values. Let's denote the number as ABCD, where A is the thousands place, B is the hundreds place, C is the tens place, and D is the ones place. From the given information, we can form the following equations: B = A - 4, C = A + 1, and D = B + 5. By substituting the first equation into the second and third equations, we get C = (B + 4) + 1 = B + 5. Therefore, the number is 6953.
Having: 9 ten-thousands → 90,000 the same number of thousands as ten thousands → 9 ten-thousands: 9 thousands → 9,000 8 fewer hundreds than ten-thousands → 9 ten-thousand: 9 - 8 = 1 hundreds → 100 6 more tens than hundreds → 1 hundreds: 1 + 6 = 7 tens → 70 6 fewer ones than thousands → 9 thousands: 9 - 6 = 3 ones → 3 → the number is 90,000 + 9,000 + 100 + 70 + 3 = 99,173.
It is 4692.
The number has 1 thousand. It has 8 more hundreds than thousands so it has 8 more hundreds than 1. That is, it has 9 hundreds. It has 1 fewer tens than hundreds so it has 1 fewer tens than 9. That is, it has 8 tens.It has 2 fewer ones than tens so it has 2 fewer ones than 8. That is, it has 6 ones. So the number is 1986.