11.5
0.0435
23
0.1522
23 x 12 = 276
LCD of 23 and 12 is 276.
69
250.9091
276 divided by 4 = 69
276 ÷ 23 = 12
The least common multiple of 12 and 23 is 276.
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.