1, 3, 7, 9, 21 and 63: 1 x 63, 3 x 21, 7 x 9
two prime numbers when added together will equal 63: 2 + 61
They are: -7*9 = -63
81
There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.
1 x 63, 3 x 21, 7 x 9
189
1, 3, 7, 9, 21 and 63: 1 x 63, 3 x 21, 7 x 9
two prime numbers when added together will equal 63: 2 + 61
They are: -7*9 = -63
63 and 65 are the number
81
7x9=63
The two numbers that add to 16 and multiply to 63 are 7 and 9. This is because 7 + 9 = 16 and 7 * 9 = 63. These numbers satisfy both conditions simultaneously, making them the correct solution to the problem.
The two numbers that times eachother to equal to 63 are 9 and 7........... (9x7=63)
First you need to break the numbers into their prime factors. In this case we get: 63 = 3x3x7 21 = 3x7 The next step is to identify any common prime factors. In this case both have a 3 and a 7 as prime factors. Multiply these together and you get 3x7 = 21. This is the HCF. To find the LCM you just multiply the numbers together and divide by the HCF. 63x21/21 = 63 Thus 63 is the LCM.
the two numbers to equal to 63 is 9 and 7.