980
There are 4 of them which are 2*3*3*3 = 54
There can only be 3 of them because as a product of its prime factors: 5*5*5 = 125
The prime factorization of 735 is (3 \times 5 \times 7 \times 7). However, since 7 is repeated, it does not constitute four distinct prime numbers. The four prime numbers that multiply to give 735, including repetition, are 3, 5, and two instances of 7. Thus, the prime numbers are 3, 5, 7, and 7.
The prime factorization of 225 is (3^2 \times 5^2). To express this as a product of four prime numbers, we can write it as (3 \times 3 \times 5 \times 5). Thus, the four prime numbers that multiply to make 225 are 3, 3, 5, and 5.
2)490 5)245 7)49 7)7 = 1 When reduced to '1' Then the four numbers are 2,5,7,7. All prime numbers.
If the two prime numbers are different: You get the two prime numbers, plus 1, plus the product. For example, if you multiply 2 x 3 = 6, the factors of 6 are 2, 3, 1, and 6. If the two prime numbers are the same: You get the prime number, 1, and the product. For example 2 x 2 = 4. The factors of 4 are 2, 1, 4.
They are: 5*5*5*7 = 875
There are only 3 of them because as a product if its prime factors: 3*7*11 = 231
There are 4 of them which are 2*3*3*3 = 54
There can only be 3 of them because as a product of its prime factors: 5*5*5 = 125
Because the four smallest prime numbers are 2, 3, 5, and 7. If you multiply these four together you get 210 (which makes 210 the smallest number divisible by four unique prime numbers).
2)490 5)245 7)49 7)7 = 1 When reduced to '1' Then the four numbers are 2,5,7,7. All prime numbers.
616
2 x 2 x 7 x 7
2 x 2 x 2 x 5
As a product of its prime factors: 2*2*5*5 = 100
3 x 3 x 7 x 7