Suppose the lower left corner is (0, 0), and the upper right corner is (a, b). Then the upper left corner would be something like (x, b). The lower right corner, because of the symmetry of the parallelogram, would then have to be (a-x, 0).
It is the sum of the y-coordinates of the vertices divided by the number of vertices.
A parallelogram has 4 vertices
A parallelogram has four vertices- it's a quadrilateral.
Yes and it has 4 of them.
That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
It is the sum of the y-coordinates of the vertices divided by the number of vertices.
A parallelogram has 4 vertices
All parallelograms have 4 vertices.
A parallelogram has four vertices- it's a quadrilateral.
4 sides and 4 vertices
Four.
4.
Yes and it has 4 of them.
That depends on where the triangle ABC is located on the Cartesian plane for the coordinates of its vertices to be determined.
how does translation a figure vertically affect the coordinates of its vertices
A parallelogram does not intersect coordinates!
Oh, dude, a parallelogram has four vertices. Yeah, it's like a fancy way of saying it has four corners. So, if you ever need to count 'em, just look for those four points where the sides meet. Easy peasy!