The measures could be centimetres, kilometres or light years.
The measures could be centimetres, kilometres or light years.
The measures could be centimetres, kilometres or light years.
The measures could be centimetres, kilometres or light years.
The base is 13 units and the height is 6 units so use these dimensions to determine the 3rd side of the triangle.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
It is impossible to find the height of a triangle with just it's base.
The area of a triangle is one-half the product of the triangle's base and height. The height of an equilateral triangle is the distance from one vertex along the perpendicular bisector line of the opposite side. This line divides the equilateral triangle into two right triangles, each with a hypotenuse of 9c and a base of (9/2)c. From the Pythagorean theorem, the height must be the square root of {(9c)2 - [(9/2)c]}, and this height is the same as that of the equilateral triangle.
To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle. To find the area of a triangle find the base and the height of the triangle. Then multiply the base by the height, then divide by 2. To find the perimiter of a triangle add together the outside edge of the triangle.
It is not possible.
The base is 13 units and the height is 6 units so use these dimensions to determine the 3rd side of the triangle.
Parallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*HeightParallelogram = Base*Height Triangle = 0.5*Base*Height
That the area of a triangle = 0.5*base*height
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
The area of any triangle is defined as half the base multiplied by the height.
it is possible, if the triangle is bigger than the rectangle, for example the rectangle has a base of 5 and height of 2-- so the area is 10; and then the triangle has a base of 5 and a height of 4-- the area is also 10.
It is impossible to find the height of a triangle with just it's base.
Because the area of a triangle = 0.5*base*height
The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.
No. I can only find the height in terms of the base (and area) of the triangle, or the base in terms of the height (and area) of the triangle. Specifically, since: area = 1/2 x base x height ⇒ 22 = 1/2 x base x height ⇒ 44 = base x height I can rearrange that to: height = 44 ÷ base or base = 44 ÷ height For example, the triangle could have a base of 11 units and a height of 4 units; alternatively, the triangle could have a base of 10 units and a height of 4.4 units; or, the triangle could have a height of 2 units and a base of 22 units; etc.
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.