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81 = 3 x 3 x 3 x 3, ie it has no factors which will make an even number, so there is no solution to your problem as stated. If however you meant ADD to 81, the the answer is 11, 12, 13, 14, 15 and 16.
The numbers that add to get 6 and multiply to get 81 are 3 and 3.
(x) + (x + 2) + (x + 4) = 81 3x + 6 = 81 3x = 75 x = 25 The three numbers are 25, 27, and 29
x + (x+2) + (x+4) = 249 3x+6=249 3x=243 x=81 81, 83, and 85
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
The numbers are 5, 6, and 7.