The numbers that add to get 6 and multiply to get 81 are 3 and 3.
(x) + (x + 2) + (x + 4) = 81 3x + 6 = 81 3x = 75 x = 25 The three numbers are 25, 27, and 29
x + (x+2) + (x+4) = 249 3x+6=249 3x=243 x=81 81, 83, and 85
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
The numbers are 5, 6, and 7.
The numbers that add to get 6 and multiply to get 81 are 3 and 3.
You multiply the previous number by consecutive numbers starting with 1.
(x) + (x + 2) + (x + 4) = 81 3x + 6 = 81 3x = 75 x = 25 The three numbers are 25, 27, and 29
x + (x+2) + (x+4) = 249 3x+6=249 3x=243 x=81 81, 83, and 85
Well, to get such numbers, you multiply 6, by two different numbers. Make sure the two numbers are relatively prime. One way to ensure this is to use two consecutive numbers. For example: 6 x 4 6 x 3
numbers with patterns; consecutive numbers: 1,2,3,4... consecutive even numbers: 2,4,6,8... and many more Consecutive numbers are numbers that come one after another. For example 5, 6, 7 or 99 and 100.
Consecutive numbers are those in a continuous sequence for a given subset of numbers, usually integers. Example of consecutive integers: 6, 7, 8, 9 Consecutive odd numbers: 7, 9, 11, 13 Consecutive even numbers: 6, 8, 10, 12 Consecutive multiples of 10: 30, 40, 50, 60 Consecutive prime numbers: 5, 7, 11, 13, 17
Every sixth number will be a multiple of 6, so you need at least six consecutive numbers to guarantee that one of them will be divisible by 6.
The numbers are 5, 6, and 7.
54
1 x 162, 2 x 81, 3 x 54, 6 x 27, 9 x 18
The prime factorization of 180 is 2x2x3x3x5. Six consecutive prime numbers do not exist in its factorization.