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Let's denote the two square numbers as (a^2) and (b^2). We are given that (a^2 - b^2 = 7). Using the difference of squares formula, we can rewrite this as ((a + b)(a - b) = 7). Since 7 is a Prime number, the only way to factor it is 1 * 7. Therefore, we have two possible pairs of values for (a) and (b): (4, 3) or (-4, -3).
4 and 3, the squares being 16 and 9.
42 - 32 = 7
4 and 3
3
you subtract the top 2 numbers and then leave the denominators the same like: 7/8-4/8=3/8. Get it?