Let's denote the two square numbers as (a^2) and (b^2). We are given that (a^2 - b^2 = 7). Using the difference of squares formula, we can rewrite this as ((a + b)(a - b) = 7). Since 7 is a Prime number, the only way to factor it is 1 * 7. Therefore, we have two possible pairs of values for (a) and (b): (4, 3) or (-4, -3).
4 and 3, the squares being 16 and 9.
42 - 32 = 7
4 and 3
3
you subtract the top 2 numbers and then leave the denominators the same like: 7/8-4/8=3/8. Get it?
5 and 2
16 - 9 = 7
4 and 3, the squares being 16 and 9.
42 - 32 = 7
They are: 16 amd 9
4 and 3
???
3
You can either subtract the whole number portions, then subtract the numerators, or you can convert the mixed numbers to improper fractions, subtract the numerators, and simplify. For example, 3 5/7 - 2 1/7 can be handled as 3 - 2 and 5/7 - 1/7, or as 26/7 - 15/7; either way, it's 1 4/7.
Subtract is to take away a certain portion of a number. For example, if you subtract 5 from 7 (7-5), you take off 5 parts of 7, and get 2 as your answer.
They are: 16 and 9 because 16-9 = 7
I donβt know