156
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50, 51, 52
153/3 = 51The middle number is 51, so the numbers are...50, 51 and 52
153, 155, and 157
There is no set of three consecutive integers for 106.
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers