There is only one common factor of 5, 3, 7: 1
The greatest common denominator is infinite.
The GCF is 1.
The prime factors are: 15 = 3 * 5 35 = 5 * 7 75 = 3 * 5 * 5 So the greatest common factor is 5.
The greatest common factor of 144 and 175 is 1. Factoring completely, we determine: 144 = 12 * 12 = 3 * 3 * 4 * 4 = 3 * 3 * 2 * 2 * 2 * 2 * 1 175 = 7 * 25 = 7 * 5 * 5 * 1 Since the only factor these have in common is 1, 1 is their greatest common factor.
There is only one common factor of 5, 3, 7: 1
Factor out each term to get: 77 = 7 x 11 105 = 5 x 21 = 5 x 3 x 7 = 3 x 5 x 7 Since these terms have 7 in common, 7 is the common factor.
735/3=245/7=35/7=5 2625/3=875/7=125/5=25/5=5 ring the factors in common which are 3*7*5 =105 highest common factor
The greatest common denominator is infinite.
25 = 5*5 35 = 5*7 45 = 3*3*5 So the greatest common factor is 5.
The prime factors of 180a2 are 2, 2, 3, 3, 5, a, and a. The prime factors of 210a are 2, 3, 5, 7, and a. The prime factors in common are 2, 3, 5, and a, so the greatest common factor is 2 x 3 x 5 x a = 30a. If a is divisible by 7, there would be two factors of 7 in a2, so the extra 7 would be another factor in common with 210a, in which case the greatest common factor would be 7 x 30a = 210a
140
The prime factorization of 525 is 3*7*5*5The prime factorization of 630 is 2*3*3*5*7The factors they have in common are 3*5*7 = 105, so the greatest common factor is 105.
21 = (3)(7)35 = (5)(7)7
The GCF of 2, 3, 5, 7, and 11 is 1.2, 3, 5, 7, and 11 are all prime numbers. Each has only two factors ... itself and '1'. The greatest factor common among them is the only factor common among them ... '1'.
prime factor all 3 45=3*3*5 75=3*5*5 105=7*3*5 Select the common factors 3*5 = 15, the GCF
The GCF is 1.