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One relationship is that the sum of the nth and the previous triangular numbers is equal to the nth square number.

That is

T(n-1) + T(n) = S(n)

where T(n) is the nth triangular number and S(n) is the nth square number.

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10y ago

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T(n-1) + T(n) = S(n)

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9y ago
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Q: What are the connection between triangular numbers and square numbers?
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