No. The first five cube numbers are 1, 8, 27, 64, 125.
1, 8, 27, 64. 0 is also a cube number.
don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
Yes there are 6 numbers on a dice and the prime numbers are 2 3 and 5
The volume of a cube is length times width times height. As it is a cube these three numbers are the same, so x^3 is the volume of a cube, hence the name 'cubed'.
The first six cube numbers are equal to 1, 2, 3, 4, 5 and 6 cubed. Then these numbers are 1, 8, 27, 64, 125 and 216.
The first 6 cubed numbers are: 1, 8, 27, 64, 125, 216. 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 5 ^ 3 = 125 6 ^ 3 = 216
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
Square: 1,4,9,16,25,36,49,64,81,and 100 cube: sorry?!?
Let's denote the two cube numbers as (a^3) and (b^3), where (a) and (b) are integers. We are looking for two cube numbers that satisfy the equation (a^3 + b^3 = 28). By testing different values, we find that (1^3 + 3^3 = 1 + 27 = 28), so the cube numbers 1 and 3 add up to make 28.
0 cube is 0 1 cube is 1 2 cube is 8 3 cube is 27 4 cube is 64 5 cube is 125. 6 cube is 216
Total numbers on a cube = 6Even numbers on a cube = 3Probability of rolling an even number on one fair cube = 3/6 = 50% .
58524600--753 that is it and it right
No. The first five cube numbers are 1, 8, 27, 64, 125.
1, 8, 27, 64. 0 is also a cube number.
33 = 81 63 = 216 93 = 729 and 123 = 1728
Well, darling, let's break it down for you. The cube root of 100 is 5, and the cube root of 400 is 7. So, the cube numbers between 100 and 400 are 125 (5^3), 216 (6^3), and 343 (7^3). Voilà!