No. The first five cube numbers are 1, 8, 27, 64, 125.
1, 8, 27, 64. 0 is also a cube number.
don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
Yes there are 6 numbers on a dice and the prime numbers are 2 3 and 5
The volume of a cube is length times width times height. As it is a cube these three numbers are the same, so x^3 is the volume of a cube, hence the name 'cubed'.
The first six cube numbers are equal to 1, 2, 3, 4, 5 and 6 cubed. Then these numbers are 1, 8, 27, 64, 125 and 216.
The first 6 cubed numbers are: 1, 8, 27, 64, 125, 216. 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 5 ^ 3 = 125 6 ^ 3 = 216
Those are the cubes of the numbers 1-10. Just calculate the cube of 1, the cube of 2, the cube of 3, etc., up to the cube of 10.
Square: 1,4,9,16,25,36,49,64,81,and 100 cube: sorry?!?
0 cube is 0 1 cube is 1 2 cube is 8 3 cube is 27 4 cube is 64 5 cube is 125. 6 cube is 216
Total numbers on a cube = 6Even numbers on a cube = 3Probability of rolling an even number on one fair cube = 3/6 = 50% .
58524600--753 that is it and it right
No. The first five cube numbers are 1, 8, 27, 64, 125.
1, 8, 27, 64. 0 is also a cube number.
33 = 81 63 = 216 93 = 729 and 123 = 1728
don't know if I understand your question, but: there are no numbers that are both cube numbers and prime numbers 8 is a factor of 16 that is a cube number (2^3) 2 is a factor of 16 that is a prime number
none 3 x 3 x 3 = 27 4 x 4 x 4 = 64 ---------------------------- Every number has a cube root, just most of them are not whole numbers, so every number between 30 and 50 is a cube. If you meant what the perfect cube numbers (ie the cubes of whole numbers) between 30 and 50, then the answer is, as above, none.