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Any two numbers that you choose can be next. It is easy to find a rule based on a polynomial of order 5 such that the first four numbers are as listed in the question followed by the chosen next number. There are also non-polynomial solutions. Short of reading the mind of the person who posed the question, there is no way of determining which of the infinitely many solutions is the "correct" one.For example, U(n) = (-4*x^4 + 40*x^3 - 140*x^2 + 215*x - 75)/3 gives the next number as 0,U(n) = (-31*x^4 + 310*x^3 - 1085*x^2 + 1670*x - 576)/24 gives the next number as 1, and so on.The simplest rue, based on a linear expression, gives U(5) = 32 and U(6) = 37.
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The sum of two numbers is 22 the difference is 12 what are the two numbers?
17 and 5
What are the next three numbers in this pattern -2-7 -12?
-17, -22
Two numbers adding up to 17 out of 6 13 2 12 7 14?
No two of those numbers add to 17.
The sum of two numbers is 7 and the difference is -17 Find the numbers?
24
What two square numbers add up to 17?
the answer is 42+12=17 and this is how to double check 42+12=17 16+1=17 17=17
The sum of two numbers is 22 and the difference is 12 What are the two numbers?
The two numbers are 5 and 17.
If the sum of two numbers is 17 and the product of 60 What are the two numbers?
12 and 5 are the numbers. 12 + 5 = 17 and 12 x 5 = 60Think of the factors first.1,602,303,204,155,12 We've got a winner!!!6,10
What are the next two numbers in the pattern 3 5 9 17?
They are 33 and 65
What is the different between -12 and 5?
The difference between the two numbers is 17
What are the next 2 numbers in the following sequence 2 3 5 7 11?
This list of numbers is the list of prime numbers. Following 11, the next two numbers in the list are 13 and 17.
What is the next two numbers 20 20 19 17 14 in this sequence?
11 and 8
What numbers equal 17 when one number is greater by 5?
If this refers to the SUM of two numbers then let the lesser number be represented by a. Then, a + (a + 5) = 17 : 2a + 5 = 17 : 2a = 12 : a = 6 So the two numbers are 6 and 11.
