They are:2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71,
73, 79, 83, 89, 97, 101, 103, 107,
109, 113, 127, 131, 137 and 139.
3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139.
The prime factors of 144 are 2(4) and 3(2)That is, 144 = 2 x 2 (4 times) x 3 x 3, and those numbers are primes.
They are: 2*2*2*2*3*3 = 144
144 = 2 x 2 x 2 x 2 x 3 x 3. So, 2 and 3 are the two prime numbers.
none of these is a prime number, because the only even number that is prime is 2
To find the prime factors of 144, you can do a prime factorization" 2 x 72 = 144 2 x 2 x 36 2 x 2 x 2 x 18 2 x 2 x 2 x 2 x 9 2 x 2 x 2 x 2 x 3 x 3 = 144 This is the prime factorization of 144 because all factors are prime numbers.
There are several prime numbers that add up to 144 and of it is 71+73 =144
2x2x2x2x3x3=144
No a prime number can only be divided by 1 and itself. 144 is an even number, all even number can be divided by 2 (144/2=72) so no even numbers can be prime numbers.
The prime factors of 144 are 2(4) and 3(2)That is, 144 = 2 x 2 (4 times) x 3 x 3, and those numbers are primes.
As a product of its prime factors: 2*2*2*2*3*3 = 144
2 and 3
As a product of its prime factors in exponents: 2^4 times 3^2 = 144
They are: 2*2*2*2*3*3 = 144
No, two even numbers cannot be relatively prime.
They are not prime numbers because they have other factors aside from 1 and themselves.
11 x 11 + 23 = 144
139 and 5