The two numbers can be 479 and 958 (479 doubled). 958 only has the factors 479 and 2, so, since 2 does not factor into 479, the common factor remains 479.
958 and 1437
2 numbers have a gcf of 3 = 3 & 6, 6 &9,...
the gcf is 2 or 11
6and7 dombnut
479 and 479
The two numbers can be 479 and 958 (479 doubled). 958 only has the factors 479 and 2, so, since 2 does not factor into 479, the common factor remains 479.
Two even numbers won't have an odd GCF.
The GCF of 18, 20, and 26 is 2. The GCF of a set of numbers can't be any larger than the smallest difference between the numbers. The smallest difference within this set of numbers is 2. Since all of the numbers in the set are even, 2 is the greatest common factor.
You need at least two numbers to find a GCF.
Oh, dude, you're hitting me with some math vibes here. So, if the greatest common factor of two numbers is 479 and one is odd while the other is even, and they're not divisible by each other, then the smallest those two numbers could be is 479 and 958. The odd number would be 479 and the even number would be 958. Easy peasy lemon squeezy!
The GCF of 2 numbers can be less than either number.
2 AND 3
18 and 81
2 and 3 are relatively prime, so multiply 479 by each of them to get two numbers that have 479 as a greatest common factor and are not divisible by each other, one which will be even and one which will be odd.479 x 2 = 958479 x 3 = 1437Furthermore, this is the smallest solution. The two numbers are multiples of 479, so let's call them 479x and 479y, where 479x is even and 479y is odd. Then x must be even, and y must be odd. So x is at least 2. y is an odd number, and it can't be 1 otherwise 479y would be a factor of 479x. So y is at least 3. Theefore the two numbers are at least 479*2 and 479*3.
958 and 1437
The GCF of 6, 8, and 14 is 2. The GCF can't be any larger than the smallest difference between any two numbers in the set. This smallest difference is 8-6 = 2. Since two is a factor of all three integers in the set, the GCF must be 2.