6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b
3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2b
Adding the two equations gives: 18 = 9a so that a = 2
Substituting for a in the first gives 12 = 6 - 2b so that b = -3
6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b
3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2b
Adding the two equations gives: 18 = 9a so that a = 2
Substituting for a in the first gives 12 = 6 - 2b so that b = -3
6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b
3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2b
Adding the two equations gives: 18 = 9a so that a = 2
Substituting for a in the first gives 12 = 6 - 2b so that b = -3
6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b
3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2b
Adding the two equations gives: 18 = 9a so that a = 2
Substituting for a in the first gives 12 = 6 - 2b so that b = -3
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6 is the average of 2a and a - 2b so 12 = 2a + a - 2b = 3a - 2b
3 is the average of 2a - b and 4a + 3b so 6 = 2a - b + 4a + 3b = 6a + 2b
Adding the two equations gives: 18 = 9a so that a = 2
Substituting for a in the first gives 12 = 6 - 2b so that b = -3
You can't find the midpoint of a general line as a general line is infinitely long. However you can find the midpoint of a Pacific line between two points add up the x values divide by 2. Add up the y values divide by 2. That is the coordinate of the midpoint of a Pacific line.
Draw a line joining a point and its image and find its midpoint. Repeat for another pair of point and its image. The line joining these midpoints is the line of reflection.
It will have no y intercept and it is: y = 0.125x
It is the midpoint of the straight line joining E and A.
== == An isosceles triangle with sides 5, 5, 3. The only line of symmetry is the line joining the midpoint of the side of 3 units to its opposite vertex.