Prime numbers (except for 5) can't be divisible by 5.
If two numbers are divisible by 5 then both cannot be prime.
No. To be relatively prime, numbers have to have a GCF of 1. Numbers ending in 5 are divisible by 5.
They are all divisible by 1 because they are all prime numbers.
The four smallest prime numbers are 2, 3, 5, and 7. Their product is 2 x 3 x 5 x 7 = 210. Thus, the smallest number that is divisible by four different prime numbers is 210.
All numbers are divisible by all non-zero numbers. 14 is not evenly divisible by 5.
no because 5,15,25,35,45,55,65,75,85,95,105...are not divisible by 10.10,20,30,40,50,60,70,80,90,100 are divisible by 10 and 5
All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.All numbers that end with 5 are divisible by 5.
2310, for one.
Prime numbers are only divisible by 1 and itself... so no prime number can be divisible by the numbers you listed.
There are no prime numbers divisible by 435. 435 is divisible by 3, 5 and 29
Yes. The prime factorization of 75 is 3 x 5 x 5. So 75 is divisible by the two prime numbers 3 and 5.
No, prime numbers are divisible only by themselves and 1. 2005 is also divisible by other numbers such as 5
105105 is divisible by 5 different prime numbers.
5, all other numbers ending in 5 are divisible by 5.
5 and 2 are the only prime numbers that end in a 5 or 2. A prime number is by definition only divisible by 1 and itself, and all other whole numbers ending in 5 or 2 are divisible by 5 or 2, respectively. Numbers that are not whole numbers cannot be prime.
Because the definition of twin primes is: two prime numbers with a difference of 2. 3 and 5 are both prime numbers, and their difference is 5 - 3 = 2 → they are twin primes.