Every number besides 0 can be safely divided into 3, 5, and 7, although most of the resultant quotients will have a non-zero remainder.
If you require all three quotients to have a remainder of zero, then the divisor must be the reciprocal of any non-zero integer.
If you require the divisor itself to be a non-zero integer, then there are only two numbers that can be divided into 3, 5, and 7 without a remainder, 1 and -1.
Any multiple of 140.
975
35 and all of its integral multiples
The LCM of (5, 6, 7) is 210.
4, 5 5, 6 6, 7 7, 8 8, 9 9, 10
7 and 5 are prime numbers, but 3*2=6
no need for 3 as it already goes in to 6 so 5 6 7 go in to 210 210 = 5 x 42 = 6 x 35 = 7 x 30
Go decimal: 5/6 = 0.83, 6/7 = 0.86 so 5/6 is smaller. Alternatively, 5/6 = 35/42, 6/7 = 36/42 5/6<6/7 83.313333<85.11428
51
5 6 -8 7 6 -5 5 5 5 -5 6 -6 6 5 6 -8 7 6 -5 6 6 6 -6 -7 7 7 -8 6 6 -7 -6 6 5 6 7 -6 7 -8 7 -7 6 5 6 -8 7 6 -5 6 6 6 -6 -7 7
5+6+7 , 5+7+6 , 6+5+7, 6+7+5 , 7+5+6, and 7+6+5
It does not go in equally. 7 times 5 is 35 7 times 6 is 42
41 ÷ 7 = 5 remainder 6
1. As 7 is a prime number.
go 5-6=-1go -1-7=-8 (-1+-7)=-8aswer is -8
It will certainly go ito 7! = 1*2*3*4*5*6*7 = 5040, although that is not the smallest positive integer that they will go into.
4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4 7 -7 -6 6 -7 6 -6 -5 6 7 -7 -6 6 -7 7 -7 -6 6 -7 6 -6 -5 6 5 -5 5 4 4 4 -5 6 -6 6 5 4 -5 6 -6 6 4 -5 6 -6 6 5 5 -5 5 4 4