Any number of the form 36*k, where k is an integer, is evenly divisible.
36 = 3 x 12 = 4 x 9
then 72 108 144 180 216 252 288 324 and so on ...
Any multiple of 36.
36
36 (9 x 4 = 36) and (3 x 12 = 36) 3+9=12 3 x 9 = 27 9 / 3 = 3 The numbers 3 and 9 go into many numbers. The most obvious is 9. (3 x 3=9) (9 x 1 =9). Another number 3 and 9 go into is 27.
No. Three is not evenly divisible by four.
1, 2, 4 1, 3, 9 1, 2, 3, 6, 9, 18
The LCM of 3, 4, 9, and 10 is 180
36 [ They can also all go into 9, (9/6 is 1.5, 9/4 is 2.25, 9/3 is 3, and 9/9 is 1) etc! ]
4 with 3 remaining 39 - 3 = 36 = 9 x 4
2!, 3!, 4
3/4 ÷ 4/9 = 3/4 × 9/4 = (3×9)/(4×4) = 27/16 = 1 11/16
4 times, remainder 3
9 times with a remainder of 3 or 9.75 times
1, 2, 3, 4, 6, 9, 12, 18 and 36 go into 36
see if 4+4=3 then value of 3=4+4 (eq 1) now we need to find out 9+9=? we can write 9+9 as 3+3+3+3+3+3 (eq 2) now by substituting the value of 3 from eq 1 in eq 2 we will get (4+4)+(4+4)+(4+4)+(4+4)+(4+4)+(4+4)=48 so 9+9=48
36
3/4 + 9/4 = 12/4 = 3
3/4 divided by 1/3 = 3/4 x 3/1 = 9/4 = 2 1/4
Four times... with 12 remaining.