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correct for apex
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The correct answer is 6.5 for apex.
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Q: What coefficient would the O2 have after balancing C3H8 O2 CO2 H2O?
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Related questions

What coefficient would the O2 have after balancing C3H8 plus O2 CO2 plus H20?

5


What coefficient would O2 have after balancing C3H8 O2 CO2 H2O?

C3H8 + 5O2 = 3CO2 + 4H2O, so the coefficient for O2 is 5


What coefficient would the O2 have after balancing C4H8 O2-CO2 H2O?

the answers is 6 _apex


What is the coefficient of carbon dioxide after balancing the following equation khco3 s k2co3 s h2o g co2 g?

3


If 100.0g C3H8 is burned completely how many grams CO2 would be produced if the only source of carbon is C3H8?

The reaction isC3H8 + 5O2 ----> 3CO2 + 4H2O100g of propane is approx 2.27 moles.From the equation above, we see that the ratio of C3H8 to CO2 is 1:3, therefore the number of moles of CO2 which form is approx 6.82.This relates to a mass of 300g of CO2


How many grams of CO2 will be produced by burning 34.3 gram of C3H8?

[ 34.3(gC3H8) / 44(g/mol C3H8)] * [ 3mol CO2 / 1molC3H8 ] * 44(g/mol CO2) = 103 gram CO2


How do you balance c3h8 plus o2 equals co2 plus H2O?

C3h8 + 5o2 -> 3co2 + 4h2o


How do you balance C3H8 plus O2 yields CO2 plus H₂O?

C3h8 + 5o2 --> 3co2 + 4h2o


Try balancing the equations for the reactions in which propane (C3H8) and butane (C4H10) are burned in oxygen to form carbon dioxide and water.?

Burning of propane:CH3H8 + 5 O2 = 3 CO2 + H2OBurning of butane:2 CH4H10 + 13 O2 = 8 CO2 + 10 H2O


When 2.13 moles of C3H8 burn in excess oxygen how many moles of CO2 will be formed assuming complete combustion?

Out of one mole C3H8 three moles carbondioxide (CO2) are formed by complete combustion of it.So 2.13 mole C3H8 make 3*2.13 mole CO2 = 6.39 moleCO2


What coefficient would the H2O have after balancing C4H10 plus O2 CO2 plus H2O?

2c4h10 + 13o2 => 8co2 + 10h2o (I am having some trouble with my typography today, but all those letters above should be capitalized.)


What is the balanced reaction of propane c3h8?

If you mean the balanced reaction of the combustion of propane, it is: C3H8 + 5 O2 ---> 3 CO2 + 4 H2O