To combine the powers, you can add the exponents. For example:10^2 times 10^3 = 10^5
A number is in exponential form when it is written with a base and an exponent.
No.
Most scientists use it but there are also others. Many people use the terms millions, billions and so on in finance, economics and so on and these are simply selected exponential exponential terminology.
Yes.
Algorithms which have exponential time complexity grow much faster than polynomial algorithms. The difference you are probably looking for happens to be where the variable is in the equation that expresses the run time. Equations that show a polynomial time complexity have variables in the bases of their terms. Examples: n^3 + 2n^2 + 1. Notice n is in the base, NOT the exponent. In exponential equations, the variable is in the exponent. Examples: 2^n. As said before, exponential time grows much faster. If n is equal to 1000 (a reasonable input for an algorithm), then notice 1000^3 is 1 billion, and 2^1000 is simply huge! For a reference, there are about 2^80 hydrogen atoms in the sun, this is much more than 1 billion.
Algorithms which have exponential time complexity grow much faster than polynomial algorithms. The difference you are probably looking for happens to be where the variable is in the equation that expresses the run time. Equations that show a polynomial time complexity have variables in the bases of their terms. Examples: n^3 + 2n^2 + 1. Notice n is in the base, NOT the exponent. In exponential equations, the variable is in the exponent. Examples: 2^n. As said before, exponential time grows much faster. If n is equal to 1000 (a reasonable input for an algorithm), then notice 1000^3 is 1 billion, and 2^1000 is simply huge! For a reference, there are about 2^80 hydrogen atoms in the sun, this is much more than 1 billion.
To express 58 as a quotient of two exponential terms, we can represent it in the form ( \frac{a^m}{b^n} = 58 ), where ( a, b ) are bases and ( m, n ) are their respective exponents. The number of ways to do this depends on the choices of ( a ), ( b ), ( m ), and ( n ), which can vary widely. Specifically, we need pairs ( (m, n) ) such that ( a^m = 58 \cdot b^n ). The specific count of valid pairs will depend on the integer factorization of 58 and the constraints on ( a ) and ( b ). Thus, there isn't a straightforward count without additional constraints or definitions on the bases and exponents.
You use the FOIL method. First terms Outer terms Inner terms Last terms.
As it is given 43*33 but in terms of prime factors, it would be 26*33
210 x 510
3.7 bilion = 28*58*37
The question cannot be answered because it is based on a complete lack of understanding. You CAN multiply or divide like terms.