106
If the concentrate is 6% of the final, then:
6% of 100 gallons = 6/100 x 100 gallons
= 6 gallons is concentrate
(100% - 6%) of 100 gallons = 94% of 100 gallons
= 94/100 x 100 gallons
= 94 gallons is water.
50 gallons @ 3% must be added.
132 gallons 16 : 84 of 60 gallons = 9.6 : 50.4 gallons 80 : 20 of 132 gallons = 105.6 : 26.4 gallons added = 115.2 : 76.8 gallons = 1.5:1 ( 60:40)
NO AFENCE, BUT THAT IS AN IMPOSIPLE QUESTION TO ANSWER. MAYBE SOMEONE WILL ANSWER THAT FOR YOU. GOOD LUCK!
2 gallons.
4 gallons Let x be the amount of antifreeze needed to be added. We know that the total amount of antifreeze in the new solution must equal the amount of antifreeze in the old solution + x: .40*(x+12)=x+.20*12 .60x=2.40 x=4 gallons
0.25 gallons of water (or 1 quart)
It is added and used for decorative or architectural concrete
10 percent added to 4.86 is 5.346.
Suppose x gallons of 50% antifreeze is added to 90 gallons of 30% antifreeze. Total active ingredient in mixture = 0.5*x + 0.3*90 = 0.5*x + 27 Total volume of mixture = x + 90 gallons Concentration of mixture = (0.5*x + 27)/(x + 90) = (50x + 2700)/(x + 90) percent This should be 40% So 40 = (50x + 2700)/(x + 90) That is, 40x + 3600 = 50x + 2700 so that 900 = 10x and x = 90 So, add 90 gallons of the 50% antifreeze. In fact, for this particular example, there is a short cut. You are adding antifreeze of two concentrations to get a result whose concentration is EXACTLY halfway. This requires the same amount of the two concentrations to be added together.
1.2 gallons
it is a base
First off do not use tap water. Use only distilled water. You will need to add 3 gallons of distilled water to the solution to get 60% antifreeze and 40% distilled water or a 60/40 mix.