Since an integral is the area under a curve, it is easy to see that the integral of 1 (i.e., the constant function whose value is always 1), from 0 to 0.75, is equal to 0.75. Of course, you can also come up with more complicated curves that have the same value under the curve, within a certain range. What's more, in just about any "well-behaved" function you can find an interval so that the area underneath the curve is equal to any value you want. That would even include functions which are always negative - just switch the integration limits in this case.
4 divided by 3 does NOT equal 75% it equals 133.33%
-1
7x3 equals 21 with no remainder.Than 21+4 equals 25. and 15 is the number which can be divided by 7 and answer will be 3 reminder 4
2/5 divided by 3/10 equals .4/.3 which equals 4/3 or 1.33333333
1/3 divided by 4 = 1/12
No. The divisor may be an integral multiple of the dividend. For example, 3 1/2 divided by 1 3/4 equals 2. (7/2 divided by 7/4)
4 divided by 3 does NOT equal 75% it equals 133.33%
3
1 3 DIVIDED by 3 time 4 divided by 4, 3 time 4 = 12 divided by 4 = 3 then 3 divided by 3 equals 1
-1
7x3 equals 21 with no remainder.Than 21+4 equals 25. and 15 is the number which can be divided by 7 and answer will be 3 reminder 4
2/5 divided by 3/10 equals .4/.3 which equals 4/3 or 1.33333333
1/3 divided by 4 = 1/12
12.75
It's 4. 12 divided by 4 equals 3 40 divided by 4 equals 10
36 divided by 9 equals 4
3 and 1/2 divided by 4 equals .875