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It has to be a prime multiple of 7 >= 49. Simple trial and error rules out 7*7, 7*11, and 7*13. 7*17 = 119 works: 119 = 2*59 + 1 119 = 3*39 + 2 119 = 4*29 + 3 119 = 5*23 + 4 119 = 6*19 + 5 119 = 7*17
Since 17 is a factor of 119, the remiander will be the same modulo 17. Thus, the remainder, on division by 17 would be 19 except that 19 contains one more 17 - leaving a final remainder of 2.
119 divided by one fifth = 23.8
29.75
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