145
WORKAn engine is used to lift a beam weighing 9800 n up to 145 m how much work must the engine do to lift this beam?Solution1.This is what you know:force: F =9800 n distance: d =145 m2.This is what you need to find out:work: W = ? J3.This is the procedure you need to use:Substitute the known values f= 9800 n and d = 145 m into the work equation:W = Fd = (9800 N)(145 m) = N·m = 1421000 J4.Check your answer:Check your answer by dividing the work you calculated by the distance given in the problem. The result should be the force given in the problem.
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Peterson Number:145 = 1! + 4! + 5!number=sum of (factorials of digits)
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145 plus 68 is equal to 213.
140 + 145 + 132 + 128 = 545
95+65+140+145+150 = 695
545
545
Assuming the rules of BODMAS, 132 + 140 + 145 + (128/4) = 449.
145.
151
145
545
The answer is 545
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