Who do solve FLT some lines?
I like back into multidimensional space where were born to be
sleeping forever thousands autumn.
Pierre De Fermat's last theorem.
The conditions.
x,y,z,n are the integers >0 and n>2.
z^n=/x^n+y^n.
Assumptions
z^3=x^3+y^3.
Therefore
z=(x^3+y^3)^1/3.
I define .
F(x,y)=(x^3+y^3}^1/3 - [ (x-x-1)^3+(y-x-1)^3]^1/3.
Therefore
[z-F(x,y)]^3={ (x^3+y^3)^1/3 - (x^3+y^3}^1/3 + [
(x-x-1)^3+(y-x-1)^3] ^1/3 }^3={ [(x-x-1)^3+(y-x-1)^3]^1/3 }^3
=(x-x-1)^3+(y-x-1)^3= (y-x-1)^3-1.
Because
[z-F(x,y)]^3=(y-x-1)^3-1 .
Attention
[(y-x-1)^3-1 ] is an integer , [(y-x-1)^3-1 ]^1/3 is an
irrational number therefore [(y-x-1)^3-1 ]^2/3 is an irrational
number too.
Example
(2^3-1) is an integer , (2^3-1)^1/3 is an irrational number and
(2^3-1)^2/3 is an irrational number too.
Because
z-F(x,y)=[y-x-1)^3-1]^1/3.
Therefore
z=F(x,y)+[(y-x-1)^3-1] ^1/3.
Therefore
z^3=[F(x,y)]^3.+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+3F(x,y)*[(y-x-1)-1]^2/3+[(y-x-1)^3-1].
Therefore
3F(x,y)*[(y-x-1)^3-1]^2/3+[F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1]
- z^3 =0
Because.
z-F(x,y)=[ (y-x-1)^3-1]^1/3.
Therefore
F(x,y)=z - [(y-x-1)^3-1]^1/3.
Therefore
3F(x,y)*[(y-x-1)^3-1]^2/3
=3z*[(y-x-1)^3-1]^2/3 -3[(y-x-1)^3-1].
Therefore.
3z*[(y-x-1)^3-1]^2/3 -
3[(y-x-1)^3-1]+[F(x,y)]^3+3[F(x,y)]^2*[y-x-1)^3-1]^1/3+[(y-x-1)^3-1]
- z^3=0..
Named
[F(x,y)]^3+3[F(x,y)]^2*[(y-x-1)^3-1]^1/3+[(y-x-1)^3-1] - z^3=
W.
We have
3z*[(y-x-1)^3-1]^2/3 is an irrational number because z is an
integer and had proved [(y-x-1)^3-1]^2/3 is an irrational
number.
And
3[(y-x-1)^3-1] is an integer because x,y are the integers.
And
3z*[(y-x-1)^3-1]^2/3 - 3[(y-x-1)^3-1]+[F(x,y)]^3+W=0.
Therefore
an irrational number - an integer+W=0.
Therefore
W is an complex irrational number.
Named
3z*[(y-x-1)^3-1]^2/3 is 3z*B
And
Named
3[(y-x-1)^3-1] is C .
Therefore
3z*B - C +W=0.
Therefore
3z*B=C-W.
Because
z is an integer.
B is an irrational number=[(y-x-1)^3-1]^2/3
Attention
(an integer)^2/3 and (an integer)^2/3 is an irrational
number.
W is an complex irrational number.
C is an integer.
Therefore.
an integer*an irrational number=an complex irrational number +
an integer.
Unreasonable.
Therefore.
z^3=/x^3+y^3
Similar
z^n=/x^n+y^n.
ISHTAR.