10 with 1 remaining 31 - 1 = 30 = 3 x 10
8 times with a remainder of 10
You multiply 10/3 or 31/3 by 3.
2, remainder 10
Imagine instead that your equation is (124/10) * (31/10), or, all things being commutative in multiplication, (124 * 31) * (1/10 * 1/10) = (124 * 31) * (1/100) = (124 * 31) / 100. Multiply the first term, and you get 3844. Once you divide from there, you get 38.44.
3 goes into 31 10 times with remainder 1.
it is 2,790
31 x 10 = 310 Therefore there is only a single zero.
10 with 1 remaining 31 - 1 = 30 = 3 x 10
3 squared times 2 times 10 32*2*10 = 9*2*10 = 180
10
8 times with a remainder of 10
You multiply 10/3 or 31/3 by 3.
31/3 or 10/331/3 or 10/331/3 or 10/331/3 or 10/3
1.99 x 10^31
1 x 10^31
8 R 10