It is so very simple and quick to get the answer, especially since, IF you need it, you can use the calculator that comes with your computer. But since you are obviously not able to do so, the answer is 256.
It is so very simple and quick to get the answer, especially since, IF you need it, you can use the calculator that comes with your computer. But since you are obviously not able to do so, the answer is 256.
It is so very simple and quick to get the answer, especially since, IF you need it, you can use the calculator that comes with your computer. But since you are obviously not able to do so, the answer is 256.
It is so very simple and quick to get the answer, especially since, IF you need it, you can use the calculator that comes with your computer. But since you are obviously not able to do so, the answer is 256.
32x + 8 – 34x
(4x-8)2 = (4x-8)(4x-8) = 16x2-32x-32x+64 = 16x2-64x+64
m*2x*8 + m*32x*7 = 16mx + 224mx = 240mx
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
If 32X + 53 = 501, then 32X = 448, and X = 448/32 = 14.
32x + 8 – 34x
(4x-8)2 = (4x-8)(4x-8) = 16x2-32x-32x+64 = 16x2-64x+64
-16x2 + x + 8 = -1/64(32x - 1 - √513)(32x - 1 + √513)
m*2x*8 + m*32x*7 = 16mx + 224mx = 240mx
40
If that's + 8, the answer is 8(3x - 1)(x - 1)
If that's + 32x, the answer is x(5x - 8)(5x - 4)
1x8 2x4 16x.5 32x.25
I read that as: (3) x (32x) x (3-2) - (32x) x (3) = 32x(3 x 3-2 - 3) = 32x (3-1 - 3) = 32x-1(1 - 32) = -8 x 32x-1 When multiplying the same base (number) to any power, keep the base and add the powers, eg: 32x x 3-1 = 32x + (-1) = 32x-1 3 x 3-2 = 31 x 3-2 = 31-2 = 3-1
32x-521 = -489
4y-32x = -28
Note that 16X is a factor of 32X [16X times 2 is 32X]. So now whether it's (32X)^4 or 32 times (X^4), that will still be the LCM, so the answer is 32X to the 4th power, just as it's stated in the question.