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How many days are in 41 years?
14,975 approximately 365 x 41 = 14,965 then every four years is leap year so add 41/4 = about 10 14,965 + 10 = 14,975
How many minutes are there in 41 years?
To calculate the number of minutes in 41 years, you would first multiply 41 by the number of days in a year (365.25 on average to account for leap years). This gives you 15,008.25 days. Next, multiply this by 24 hours in a day to get 360,198 hours. Finally, multiply by 60 minutes in an hour to find there are approximately 21,611,880 minutes in 41 years.
Find the next three numbers to the sequence of 1 2 5 14?
41 122 365
What comes comes next in the number series 2 5 14 41 122?
365 since the pattern is times three minus one
How many days between 9 September 2012 and 9 September 2013?
365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.
How many times does 205 go into 365?
365/205 = 1.7804878 or 1 160/205 = 1 32/41
What number is next in this series 2 5 14 41 122?
365.
How many days are in 41 years?
14,975 approximately 365 x 41 = 14,965 then every four years is leap year so add 41/4 = about 10 14,965 + 10 = 14,975
How many minutes are there in 41 years?
To calculate the number of minutes in 41 years, you would first multiply 41 by the number of days in a year (365.25 on average to account for leap years). This gives you 15,008.25 days. Next, multiply this by 24 hours in a day to get 360,198 hours. Finally, multiply by 60 minutes in an hour to find there are approximately 21,611,880 minutes in 41 years.
Find the next three numbers to the sequence of 1 2 5 14?
41 122 365
What number comes next. 2 5 14 41 122?
The next number works out as 365
What comes comes next in the number series 2 5 14 41 122?
365 since the pattern is times three minus one
What is 365 times 365?
365 times 365 equals 133,225.
How old is Tina from Mary Mary?
Erica(the dark hair) 41 and Tina(red hair) 39
What is 365 plus 365 plus 365 plus 308?
365 + 365 + 365 + 308 = 1,403
How many days between 9 September 2012 and 9 September 2013?
365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.365 days.
What is the probability of at least one birthday match among a group of 41 people?
The probability of at least 1 match is equivalent to 1 minus the probability of there being no matches. The first person's birthday can fall on any day without a match, so the probability of no matches in a group of 1 is 365/365 = 1. The second person's birthday must also fall on a free day, the probability of which is 364/365 The probability of the third person also falling on a free day is 363/365, which we must multiply by the probability of the second person's birthday being free as this must also happen. So for a group of 3 the probability of no clashes is (363*364)/(365*365). Continuing this way, the probability of no matches in a group of 41 is (365*364*363*...326*325)/36541 This can also be written 365!/(324!*36541) Which comes to 0.09685... Therefore the probability of at least one match is 1 - 0.09685 = 0.9032 So the probability of at least one match is roughly 90%
