* 10*10 * 100*1 * 25*4 * 50*2 * 20*5
The number that can go into both 28 and 100 is 4. This is because 28 divided by 4 equals 7 with no remainder, and 100 divided by 4 equals 25 with no remainder. Therefore, 4 is a common factor of both 28 and 100.
1, 2 and 4
The factors of 100 are 1, 2, 4, 5, 10, 20, 25, 50, and 100.The prime factors of 100 are 2 and 5.The factor pairs of 100 are 1 x 100, 2 x 50, 4 x 25, 5 x 20, and 10 x 101, 2, 4, 5, 10, 20, 25, 50, 100
In order to find the common factors of 144 and 100, we follow the following steps:Step 1: Find the HCF of 144 and 100.Prime factorization of 144 = 2x2x2x2x3x3Prime factorization of 100 = 2x2x5x5HCF(144,100) = 2x2 = 22 = 4.Step 2: Find the factors of HCF(144,100) i.e. 4. The factors of 4 are the common factors of 144 and 100.Factors of 4 are 1, 2 and 4.So, common factors of 144 and 100 are 1, 2 and 4.
Between 100 and 999 there are 448.
A quarter is 1/4 of a dollar. So 999/4= 249 and three quarter $
900 number have three digits each, 100 through 999. 100 of them have a 4 in the 100's place. Of the remaining 800, 1/10 have a 4 in the tens place. 1/10 of 800 is 80. Of the remaining 720, 1/10 have a 4 in the units place.1/10 of 720 is 72. 100 + 80 + 72 = 252 252 three-digit numbers have at least one digit that is a 4.
(1/1000) / (4/100) = (1/1000) * 100/4 = 1/40 of them. (1/1000) / (4/100) = (1/1000) * 100/4 = 1/40 of them. (1/1000) / (4/100) = (1/1000) * 100/4 = 1/40 of them. (1/1000) / (4/100) = (1/1000) * 100/4 = 1/40 of them.
It is 4 and 1,000
9000 of them. All of the numbers 1 thru 9999 EXCEPT 1 thru 999. 9999 - 999 = 9000.
Oh, dude, let me break it down for you. So, to find the numbers divisible by both 3 and 4, you need to find the numbers divisible by their least common multiple, which is 12. From 100 to 999, every 12th number is divisible by 12. So, you just need to find how many multiples of 12 are there between 100 and 999. It's like a piece of cake, you got this!
Of course, the first multiple is 1 x 999 = 999. The next three multiples (multiplying by 2, 3 & 4) are: 1998, 2997, and 3996.
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
675 of them.675 of them.675 of them.675 of them.
1/4 x 100 = 100/4 = 25
3996 ÷ 4 = 999 Therefore, there are 999 groups of 4