what is the prime factorization of 2400 using exponents 2 to the fifth power x 3 x 5 squared = 2400
2 to the 3rd power x 5 to the 2nd power = 200
the prime factorization of 12 in exponents is 2 to the second power times 3
9 = 3 ^ 2, or three raised to the second power.
In infinitely many ways. However, if you want powers of positive integers only, then you can express 64 as a power of 2, 4, 8 and of 64 itself.
22=
to me i think 2 to the power of 2x2 to the power of 2 * * * * * 16 = 24
what is the prime factorization of 2400 using exponents 2 to the fifth power x 3 x 5 squared = 2400
2 to the 3rd power x 5 to the 2nd power = 200
2 to the 3rd power times 5 to the third power
2 to the power of 5, so it'd be 2 with a small five beside it
the prime factorization of 12 in exponents is 2 to the second power times 3
2to the 3 power x 3 to the 2 power = 72
2 x 5^2 = 50
9 = 3 ^ 2, or three raised to the second power.
2 to the third power times three 2^3 x 3
Prime factorization of 98 using exponents: 2 * 7 * 7 = 2 * 7²