Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":
x = 525677.4274253485
log x = log 525677.4274253485
Now use a standard property of logarithms:
log x = 85 log 525677.42742534
log x = (85)(5.72071932882537)
log x = 486.261142950157
So, the result is approximately 10486. To get the coefficient more accurately:
x = 10486.261142950157
x = 10486 + 0.261142950157
x = 100.26114295015710486
x = 1.82449614534211 x 10486
Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":
x = 525677.4274253485
log x = log 525677.4274253485
Now use a standard property of logarithms:
log x = 85 log 525677.42742534
log x = (85)(5.72071932882537)
log x = 486.261142950157
So, the result is approximately 10486. To get the coefficient more accurately:
x = 10486.261142950157
x = 10486 + 0.261142950157
x = 100.26114295015710486
x = 1.82449614534211 x 10486
Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":
x = 525677.4274253485
log x = log 525677.4274253485
Now use a standard property of logarithms:
log x = 85 log 525677.42742534
log x = (85)(5.72071932882537)
log x = 486.261142950157
So, the result is approximately 10486. To get the coefficient more accurately:
x = 10486.261142950157
x = 10486 + 0.261142950157
x = 100.26114295015710486
x = 1.82449614534211 x 10486
Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":
x = 525677.4274253485
log x = log 525677.4274253485
Now use a standard property of logarithms:
log x = 85 log 525677.42742534
log x = (85)(5.72071932882537)
log x = 486.261142950157
So, the result is approximately 10486. To get the coefficient more accurately:
x = 10486.261142950157
x = 10486 + 0.261142950157
x = 100.26114295015710486
x = 1.82449614534211 x 10486
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Since this goes beyond the capability of most calculators, and of Excel too, you will have to get an approximation with logarithms. Better use base 10 logarithms; in Excel you can use the log() function. Call your number "x":
x = 525677.4274253485
log x = log 525677.4274253485
Now use a standard property of logarithms:
log x = 85 log 525677.42742534
log x = (85)(5.72071932882537)
log x = 486.261142950157
So, the result is approximately 10486. To get the coefficient more accurately:
x = 10486.261142950157
x = 10486 + 0.261142950157
x = 100.26114295015710486
x = 1.82449614534211 x 10486
No difference. (-8)5 = (-85) = -85
2.2514 = 85 222.69
85 = 32,768
8*8*8*8*8 = 32,768.
True
3 followed by 85 zeros is not a power of any integer.
No difference. (-8)5 = (-85) = -85
85=32768.
222bhp :)
2.2514 = 85 222.69
85 = 32,768
2 629 743 85
85%
121
85 . the answer is 32,768 :D-it is 8 to the power of 5. ;D
√645 = 85 = 32768
well the reason my coil was not getting power on my 85 mr2 was cuz the timing belt snaped