(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
9x = 4x + 45 5x = 45x = 9
The slope of any line parallel to the line described is -5. Solution: 45x+9y=36. Solve for y. 9y=36-45x. y= -5x+4 m=-5
(3/5x) = 9......we cross multiply 9 by 5x 3 = 9(5x) 3 = 45x........dividing across by 45 3/45 = x x = 1/15
3x3 - 24x2 + 45x = 3x(x2 - 8x + 15) = 3x(x2 - 3x - 5x + 15) = 3x[ x(x - 3) - 5(x - 3) ] = 3x(x - 5)(x - 3)
(5x+4)(9x+9) FOIL First (5x*9x=45x**2) Outside (5x*9=45x) Inside (4*9x=36x) Last (4*9=36) 45x**2+45x+36x+36 45x**2+81x+36 9(5x**2+9x+4x)
9(5x) = 45x simplified
5x squared
8
5x is a common factor of all terms:- 5x(x3+4x2+9)
x/2 - 5x/(61/9) = x/2 - 5x(9/61) = x/2 - 45x/61 the least common denominator is 122 = [(x)(61)]/122 - [(45x)(2)]/122] = (61x - 45x)/122 = 16x/122 = (16x ÷ 2)/(122 ÷ 2) = 8x/61
9x = 4x + 45 5x = 45x = 9
The magnification of a microscope is determined by multiplying the magnification of the objective lens by the magnification of the eyepiece. In this case, if you have a 45x objective lens and a total magnification of 225x, the eyepiece magnification would be 225x divided by 45x, which equals 5x. Therefore, the power of the eyepiece would be 5x.
The slope of any line parallel to the line described is -5. Solution: 45x+9y=36. Solve for y. 9y=36-45x. y= -5x+4 m=-5
(3/5x) = 9......we cross multiply 9 by 5x 3 = 9(5x) 3 = 45x........dividing across by 45 3/45 = x x = 1/15
The cube root of 125 is 5 -- that is 5*5*5 = 125
3x3 - 24x2 + 45x = 3x(x2 - 8x + 15) = 3x(x2 - 3x - 5x + 15) = 3x[ x(x - 3) - 5(x - 3) ] = 3x(x - 5)(x - 3)