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Add together the individual numerals (M = 1000, D = 500, C = 100, L = 50, X = 10, V = 5, I = 1) unless a smaller numeral precedes a larger one in which case subtract it from the larger ones.

→ 993 = (-100) + 1000 + (-10) + 100 + 1 + 1 + 1 = CMXCIII

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M represents 1000, C is 100, X is 10 and I represents 1. So this would be CMXCIII.

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10y ago
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Q: What is 993 in roman numerals?
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