Known: 1 = 3 [ft/yd] 10 [yd] = 10 [yd] * 1 = 10 [yd] * 3 [ft/yd] = 30 [ft]. 10 [yd] to 9 [ft] would be 30 to 9 or 10 to 3. ===============
(6 ft 10 in) + (8 ft 9 in) = (6 + 8) ft + (10 + 9) in = 14 ft 19 in But 19 in = 1 ft 7 in, so (14 ft 19 in) = 15 ft 7 in
The sum of 6 ft 10 inches and 8 ft 9 inches is 15.5833333 feet or 15 feet 7 inches.
If the given values are in feet then 5*10*9 = 450 cubic feet
distance_to_other_side = width_of_lot - (width_of_house + distance_of_house_from_side) = 56 ft 9 in - (34 ft 10 in + 5 ft 5 in) = 56 ft 9 in - 40 ft 3 in = 16 ft 6 in
299 cm = 9 ft 10 inches (approx).299 cm = 9 ft 10 inches (approx).299 cm = 9 ft 10 inches (approx).299 cm = 9 ft 10 inches (approx).
10 ft * 16 ft = 160 sq ft = 160/9 = 17.77.. recurring sq yards. 10 ft * 16 ft = 160 sq ft = 160/9 = 17.77.. recurring sq yards. 10 ft * 16 ft = 160 sq ft = 160/9 = 17.77.. recurring sq yards. 10 ft * 16 ft = 160 sq ft = 160/9 = 17.77.. recurring sq yards.
Known: 1 = 3 [ft/yd] 10 [yd] = 10 [yd] * 1 = 10 [yd] * 3 [ft/yd] = 30 [ft]. 10 [yd] to 9 [ft] would be 30 to 9 or 10 to 3. ===============
(6 ft 10 in) + (8 ft 9 in) = (6 + 8) ft + (10 + 9) in = 14 ft 19 in But 19 in = 1 ft 7 in, so (14 ft 19 in) = 15 ft 7 in
The sum of 6 ft 10 inches and 8 ft 9 inches is 15.5833333 feet or 15 feet 7 inches.
If the given values are in feet then 5*10*9 = 450 cubic feet
distance_to_other_side = width_of_lot - (width_of_house + distance_of_house_from_side) = 56 ft 9 in - (34 ft 10 in + 5 ft 5 in) = 56 ft 9 in - 40 ft 3 in = 16 ft 6 in
90 squares.
Not quite. 3 yds is equal to 9 ft.
10' X 9' = 90 sq ft 90 sq ft / 9 = 10sq yds
1 yd = 3 ft 2 yds = 6 ft 3 yds = 9 ft 4 yds = 12 ft . . . 10 yds = 30 ft
9 ft 10 in