Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.
a+b=a+b
a = 20 b = 60 c = 100
a=64 b=8 (x+16x+64)=(x+8)^2
the answer is a
4b
Yes because if 1+0=1 than 0 plus b equals b
a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
b2 + 16b + 64 can be factorized to (b+8)(b+8). If they were equal to zero as in b2 + 16b + 64=0 then b = -8.
A.
a+b=a+b
a = 20 b = 60 c = 100
A=0 b=0 c=0