H2 - 100 = (H - 10)*(H + 10)
If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised.
10
It can: For example, the linear polynomial 2x + 4 can be factorised into 2 times (x+2) So the question is inappropriate.
It is: 6(5b-7)
x2 - 41 cannot be factorised.
No, 49r^4 - 100 can be factorised.
If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised.
Assuming you are referring to the reaction of CH4 + H2O → CO + 3 H2, and not combustion of methane (CH4 + 2O2 ==> CO2 + 2H2O where NO H2 is formed), then ...100 cm3 CH4 = 0.1 litersmole ratio CH4 : H2 = 1 : 3 (see balance equation above).Liters H2 produced from 0.1 liters CH4 = 3 x 0.1 = 0.3 liters of H2 can be produced.
36a
10
It can: For example, the linear polynomial 2x + 4 can be factorised into 2 times (x+2) So the question is inappropriate.
7(3x+7)
It is: 6(5b-7)
H2=2S=32O4=64O4=64/98*100=65.3 Ans=65%
divisible by more than two numbers
(x-9)(x+1)
x2 - 41 cannot be factorised.