-98
Janiya Hyatt
Wiki User
∙ 12y agoH2 - 100 = (H - 10)*(H + 10)
If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised.
10
It can: For example, the linear polynomial 2x + 4 can be factorised into 2 times (x+2) So the question is inappropriate.
It is: 6(5b-7)
The expression cannot be factorised.
No, 49r^4 - 100 can be factorised.
If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised. If there is no common factor then the polynomial cannot be factorised.
36a
Assuming you are referring to the reaction of CH4 + H2O → CO + 3 H2, and not combustion of methane (CH4 + 2O2 ==> CO2 + 2H2O where NO H2 is formed), then ...100 cm3 CH4 = 0.1 litersmole ratio CH4 : H2 = 1 : 3 (see balance equation above).Liters H2 produced from 0.1 liters CH4 = 3 x 0.1 = 0.3 liters of H2 can be produced.
10
It can: For example, the linear polynomial 2x + 4 can be factorised into 2 times (x+2) So the question is inappropriate.
Balanced equation. 2H2 + O2 >> 2H2O ( now find limiting reactant ) 7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2 60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2 1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction) 3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O) = 62.552 grams H2O produced, so; 58 grams/62.552 times 100 = 92.7% yield of H2O, call it 93%
7(3x+7)
It is: 6(5b-7)
(x-9)(x+1)
divisible by more than two numbers
The expression cannot be factorised.