5040 ÷ 1000 = 5 r 40 1000 ÷ 40 = 25 r 0 ⇒ hcf of 5040 and 1000 is 40.
The GCF is 10.
5 is the highest common factor of 10, 25 and 40.
The GCF/HCF of 25 and 4 is 1.
The Highest Common Factor (HCF) of 120 and 160 is the largest positive integer that divides both 120 and 160 without leaving a remainder. To find the HCF, we need to determine the common factors of 120 and 160. The factors of 120 are 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120. The factors of 160 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 80, and 160. The largest common factor between 120 and 160 is 40. Therefore, the HCF of 120 and 160 is 40.
5
The HCF is 5
To work this out, you have to split the numbers into the product of their prime factors: 25 = 5x5 40 = 2x2x2x5 The next step is to identify any common factors. In this case, both numbers have a 5 as a prime factor. Thus the HCF of 25 and 40 is 5.
5040 ÷ 1000 = 5 r 40 1000 ÷ 40 = 25 r 0 ⇒ hcf of 5040 and 1000 is 40.
The HCF of 40 & 12 is... 4
The hcf of 45 and 40 is 5.
HCF(40, 63) = 1
The GCF is 25.
The GCF is 25.
The HCF of the numbers 40 and 44 is 4.
The HCF of 25 and 50 is... 25.
25