As written your question is almost total nonsense - the only answer I can give based on what you have written is:
They are a set of equations, probably describing the lengths of two line segments.
However, by doing a web search I have been able to find some more questions similar to what you have written and so been able to find what might be the CONTEXT of what you are asking.
At a guess, you have an exercise, in Algebra, where you have been told (but FAILED to tell us so we have no idea what exercise/homework you are trying to get done for you):
``PQ is a line segment with T the mid point of PQ. Calculate the length PT when given the following lengths PT and TQ''
With that context in mind:
if T is the midpoint of PQ, then PT = TQ
You have told us:
PT = TQ
→ 33x + 77 = 77x - 9
You now have an algebraic equation involving x which YOU can now solve (I had to do some hard work guessing what you wanted answered, so you can repay me by doing the work to get to the final solution - hint: collect all the x onto one side and all the numbers on the other, remembering that what you do to one side of the equals you MUST do to the other side).
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Learning how to realise what all the important facts of a problem, especially the CONTEXT (ie background information) of the question are so that you can tell them to someone else, is a very important life skill which you seem to be lacking; people can not always see what you can see and so do not always know what you know - you need to THINK about what another people are likely to not know.
35x^2 + 77x + 42
49x^2 + 77x + 30 Improved answer: 7x+57x+6 When simplified: = 64x+6
35x^2 + 77x + 42 Improved answer: 5x+67x+7 When simplified = 72x+7
2x^2-77x+119 It is not factorable if you are looking for integral factors (whole numbers). You might be able to use the quadratic formula if you wish to solve for the zeros (x-intercepts) of it.
Equations: 7x-8y = 9 and 11x+3y = -17 Multiply all terms in the 1st equation by 11 and all terms in the 2nd by 7 So: 77x-88y = 99 and 77x+21y = -119 Subtract the 1st equation from the 2nd equation: 109y = -218 => y = -2 Through substitution the solutions are: x = -1 and y = -2
35x^2 + 77x + 42
49x^2 + 77x + 30 Improved answer: 7x+57x+6 When simplified: = 64x+6
35x^2 + 77x + 42 Improved answer: 5x+67x+7 When simplified = 72x+7
14x / 77x = 2/11
2x^2-77x+119 It is not factorable if you are looking for integral factors (whole numbers). You might be able to use the quadratic formula if you wish to solve for the zeros (x-intercepts) of it.
Equations: 7x-8y = 9 and 11x+3y = -17 Multiply all terms in the 1st equation by 11 and all terms in the 2nd by 7 So: 77x-88y = 99 and 77x+21y = -119 Subtract the 1st equation from the 2nd equation: 109y = -218 => y = -2 Through substitution the solutions are: x = -1 and y = -2
85
This quadratic equation which will have two solutions can be solved by completing the square or by using the quadratic equation formula.Completing the square:x2+18x+4 = 0(x+9)2+4 = 0(x+9)2+4-81 = 0(x+9)2 = 77x+9 = + or - the square root of 77x = -9 + or - the square root of 77If you're not too sure about the procedure of completing the square your maths tutor should be familiar with it.
77 times 9 equales 793
Solution:7x - 7 = 147x = 14 + 77x = 21x = 21/7x = 3Checking:7(3) - 7 = 1421 - 7 = 1414 = 14
-- First, write the quadratic formula on the back of your hand:x = 1/2A [ -B ± sqrt(B2 - 4AC) ]-- Then, stare at your equation until it dawns on you thatA = 12B = -77C = -20-- Substitute these values of 'A', 'B', and 'C' into the quadratic formula,evaluate it for the two values of 'x', and the two solutions practicallyfall out on the floor and surrender, on their own.
77