3^3 = 27
27^2 = 729
(3^3)^2 = 3^6 = 729
The sum of the first n cubed numbers is the square of the nth triangular number.
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
They are the sixth powers of all integers.
The third cubed number is (3^3), which equals (27). Cubed numbers are obtained by raising a number to the power of three, so the first few cubed numbers are (1^3 = 1), (2^3 = 8), and (3^3 = 27). Thus, the third cubed number is 27.
The first three cubed numbers are 1, 8, and 27. These are obtained by cubing the integers 1, 2, and 3, respectively (1^3 = 1, 2^3 = 8, and 3^3 = 27).
The sum of the first n cubed numbers is the square of the nth triangular number.
The GCF is 4.
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
Between 2,827 and 2,829
They are the sixth powers of all integers.
Well, honey, the cubed numbers between 2000 and 3000 are 8 cubed (512), 9 cubed (729), 10 cubed (1000), 11 cubed (1331), 12 cubed (1728), 13 cubed (2197), 14 cubed (2744), and 15 cubed (3375). So, there you have it, sweetie!
The third cubed number is (3^3), which equals (27). Cubed numbers are obtained by raising a number to the power of three, so the first few cubed numbers are (1^3 = 1), (2^3 = 8), and (3^3 = 27). Thus, the third cubed number is 27.
9, 16, and 25 are square numbers.
The first three cubed numbers are 1, 8, and 27. These are obtained by cubing the integers 1, 2, and 3, respectively (1^3 = 1, 2^3 = 8, and 3^3 = 27).
A number can't be cubed and prime. Cubed numbers (other than 1) have more than two factors.
Three cubed is 27
That would be 294 feet cubed since there are three dimensions.