For a six digit number the most significant digit cannot be zero (it will otherwise cease to be a six digit number). So MS digit can be 1,2,3,4,5,6,7,8, or 9. The Other five digits can be 0,1,2,3,4,5,6,7,8, or 9. Hence total number of six digit numbers that can be made with 0 to 9 is 9 x 10 x 10 x 10 x 10 x 10 = 900000
The letter "X" stands for the number 10.
Let the number be x: So: 2x-4 = x-10 => 2x-x = 4-10 => x = -6
Let's call the number "x". The given equation can be translated as: x * 3 = 2 * (x + 5). Simplifying the equation, we have: 3x = 2x + 10. Subtracting 2x from both sides gives: x = 10. So the solution to the equation is x = 10.
The number of possibilities is 9 x 10 x 10 x 10 x 10 x 10 x 9 = 8,100,000.
If zero is permitted as the first digit then the number of combinations is 10 x 10 x 10 x 10 x 10 = 100000 If zero is not permitted then the number of combination is :- 9 x 10 x 10 x 10 x 10 = 90000
3x+30let x = "a number"(x+10) = "a number increased by 10"3(x+10) = "3 times a number increased by 10"Expand: 3x+30
10 x 10 = 100
You get one-tenth of a number when you divide the number by 10.
1:5 x = 10 x= 50
To get a multiple of a number, multiply that number by successive counting numbers. 10 x 1 = 10 10 x 2 = 20 10 x 3 = 30 10, 20, 30 are multiples of 10.
7 + 2x = x + 10 so 2x - x = 10 - 7 x = 3
"what" / "what number" = x (a variable)"percent" = (that number/ 100)"of" = multiply"is" = "="x = (10/100)(125.09)x = 12.509
x (x - 8) = 2xx2 - 8x = 2xx2 - 8x - 2x = 0x2 - 10x = 0x (x - 10) = 0The equation is a true statement if either factor = 0.x = 0(x - 10) = 0 ==> x = 10========================> Does [ x = 10 ] work ?x (x - 8) = 2x ?10 (10 - 8) = 2 (10)10 (2) = 2020 = 20 Yes.
Multiply a number by succesive counting numbers. 10 x 1 = 10 10 x 2 = 20 10 x 3 = 30 10, 20 and 30 are multiples of 10.
120 ---------------------------------- Let the number be x; then: 8/10 x = 96 → 8x = 96 × 10 → x = 96 × 10/8 = 120
10 x 10 = 100 50 x 2 = 100 25 x 4 = 100