If you want that as an inequality, you write:x <= -10
You can replace "<=" with the corresponding inequality symbol (less than or equal).
x>10
If zero is permitted as the first digit then the number of combinations is 10 x 10 x 10 x 10 x 10 = 100000 If zero is not permitted then the number of combination is :- 9 x 10 x 10 x 10 x 10 = 90000
10 x 10 = 100
3x+30let x = "a number"(x+10) = "a number increased by 10"3(x+10) = "3 times a number increased by 10"Expand: 3x+30
1:5 x = 10 x= 50
You get one-tenth of a number when you divide the number by 10.
Let x be the number; then: 3x = 2(x + 5) → 3x = 2x + 10 → x = 10 The number is 10.
To get a multiple of a number, multiply that number by successive counting numbers. 10 x 1 = 10 10 x 2 = 20 10 x 3 = 30 10, 20, 30 are multiples of 10.
0.6
Let the number be x: So: 2x-4 = x-10 => 2x-x = 4-10 => x = -6
7 + 2x = x + 10 so 2x - x = 10 - 7 x = 3
Let x = the numbernumber increased by 10 = x + 10
For a six digit number the most significant digit cannot be zero (it will otherwise cease to be a six digit number). So MS digit can be 1,2,3,4,5,6,7,8, or 9. The Other five digits can be 0,1,2,3,4,5,6,7,8, or 9. Hence total number of six digit numbers that can be made with 0 to 9 is 9 x 10 x 10 x 10 x 10 x 10 = 900000