The number is 81.
81
The first digit can be any one of 9 digits (anything but zero). For each of those ...The second digit can be any one of 9 digits (anything but the previous one). For each of those ...The third digit can be any one of 9 digits (anything but the previous one). For each of those ...The fourth digit can be any one of 9 digits (anything but the previous one). For each of those ...The fifth digit can be any one of 9 digits (anything but the previous one).So the total number of possible arrangements is (9 x 9 x 9 x 9 x 9) = 59,049out of a total of 99,999 different 5-digit numbers, or 59.05%.
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
The first digit can be any one of nine (all except zero). For each of those . . .The second digit can be any one of ten.Total possibilities for the first two digits = 9 x 10 = 90.Since the 4-digit number is a palindrome, the 3rd and 4th digits are determinedby the 1st and 2nd ones.So the total number of 4-digit palindromes is the same as the number of possibilitiesfor the first 2 digits = 90 .
The first digit can be any one of 9 digits (anything but zero). For each of those ...The second digit can be any one of 9 digits (anything but the previous one). For each of those ...The third digit can be any one of 9 digits (anything but the previous one). For each of those ...The fourth digit can be any one of 9 digits (anything but the previous one). For each of those ...The fifth digit can be any one of 9 digits (anything but the previous one).So the total number of possible arrangements is (9 x 9 x 9 x 9 x 9) = 59,049out of a total of 99,999 different 5-digit numbers, or 59.05%.
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
Since both of those numbers contains four digits, there are no three-digit numbers between them.
The first digit can be any one of nine (all except zero). For each of those . . .The second digit can be any one of ten.Total possibilities for the first two digits = 9 x 10 = 90.Since the 4-digit number is a palindrome, the 3rd and 4th digits are determinedby the 1st and 2nd ones.So the total number of 4-digit palindromes is the same as the number of possibilitiesfor the first 2 digits = 90 .
The first digit can be any one of the nine digits. For each of those . . .The second digit can be any one of four digits . . . 2, 4, 6, or 8 .Total number of possibilities = (9 x 4) = 36
Besides no repeats, we also assume that the first digit can't be zero.The first digit can be any digit except zero ... 9 choices. For each of those . . .The second can be any one of 9 digits ... zero, and the 8 that were not the first one. For each of those . . .The third can be any one of the 8 remaining digits. For each of those . . .The fourth can be any one of the 7 remaining digits. For each of those . . .The fifth can be any one of the 6 remaining digits. For each of those . . .the Sixth can be any one of the 5 remaining digits.The total number of possibilities is: (9 x 9 x 8 x 7 x 6 x 5) = 136,080 .If there were no restrictions, then 6 digits could make 1,000,000 different numbers.The restrictions have eliminated 86.4 percent of them.
Well, 47 49 51 53 are four consecutive odd numbers those total squared has for identical digits. 40000.... The square root of any number that is only four digits long all containing the same digit has a value that is not an integer.
The greatest 5 digit number is 98765. The greatest 5 digit number that doesn't contain any of those digits is 43210. The difference between them is 55555.The two five digit numbers using all ten digits once and only once between them that sum to the largest value are 97531 and 86420. They sum to 183,951 and have a difference of 11111. These two numbers are not unique ... you can switch any pair of digits between the two numbers as long as you keep them in the same position without changing the sum, though this will change the difference.