The number is 81.
The first digit can be any one of 9 digits (anything but zero). For each of those ...The second digit can be any one of 9 digits (anything but the previous one). For each of those ...The third digit can be any one of 9 digits (anything but the previous one). For each of those ...The fourth digit can be any one of 9 digits (anything but the previous one). For each of those ...The fifth digit can be any one of 9 digits (anything but the previous one).So the total number of possible arrangements is (9 x 9 x 9 x 9 x 9) = 59,049out of a total of 99,999 different 5-digit numbers, or 59.05%.
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
Ah, a 34-digit number is called a "34-digit number," my friend! Just like how a 3-digit number has three digits, a 34-digit number has 34 digits. Isn't it fascinating how numbers can come in all shapes and sizes, each one unique and special in its own way?
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
The first digit can be any one of 9 digits (anything but zero). For each of those ...The second digit can be any one of 9 digits (anything but the previous one). For each of those ...The third digit can be any one of 9 digits (anything but the previous one). For each of those ...The fourth digit can be any one of 9 digits (anything but the previous one). For each of those ...The fifth digit can be any one of 9 digits (anything but the previous one).So the total number of possible arrangements is (9 x 9 x 9 x 9 x 9) = 59,049out of a total of 99,999 different 5-digit numbers, or 59.05%.
Assuming that 2356 is a different number to 2365, then: 1st digit can be one of four digits (2356) For each of these 4 first digits, there are 3 of those digits, plus the zero, meaning 4 possible digits for the 2nd digit For each of those first two digits, there is a choice of 3 digits for the 3rd digit For each of those first 3 digits, there is a choice of 2 digits for the 4tj digit. Thus there are 4 x 4 x 3 x 2 = 96 different possible 4 digit numbers that do not stat with 0 FM the digits 02356.
Single digit primes are 2, 3, 5, 7 Single digit squares are 1, 4, 9 Neither prime nor square are 0, 6, 8 None of that makes a difference if we can't figure out what a "grerate" is. I'll guess you want to know the greatest possible number given those conditions. That would be 985.
Oh, dude, a number with 26 digits is called a "26-digit number." Like, it's not rocket science, right? Just count those digits and boom, you got yourself a 26-digit number. Math can be so chill sometimes.
The first digit can be any one of 10 digits. For each of those . . .The second digit can be any one of the remaining 9 digits. For each of those . . .The third digit can be any one of the remaining 8 digits. For each of those . . .The fourth digit can be any one of the remaining 7 digits.The total number of possibilities is (10 x 9 x 8 x 7) = 5,040
Ah, a 34-digit number is called a "34-digit number," my friend! Just like how a 3-digit number has three digits, a 34-digit number has 34 digits. Isn't it fascinating how numbers can come in all shapes and sizes, each one unique and special in its own way?
30.The first digit can be one of three digits {3, 6, 9} corresponding to the last digit being {1, 2, 3}, and for each of those three digits, the middle digit can be one of ten digits {0 - 9}, making 3 x 10 = 30 such numbers.It is assumed that a 3 digit number is a number in the range 100-999, excluding numbers starting with a leading zero, eg 090 is not considered a 3 digit number (though it would be a valid 3-digit number for a combination lock with 3 digits).
It is a number with two digits in it. So it goes into the "tens" place of the numbers. Basically any whole number from 10 to 99. See how any number between those numbers only has 2 numbers, or digits that make up the number? 9 would only be a single-digit number, and 100 would be a triple-digit number.
Since both of those numbers contains four digits, there are no three-digit numbers between them.
The first digit can be any one of nine (all except zero). For each of those . . .The second digit can be any one of ten.Total possibilities for the first two digits = 9 x 10 = 90.Since the 4-digit number is a palindrome, the 3rd and 4th digits are determinedby the 1st and 2nd ones.So the total number of 4-digit palindromes is the same as the number of possibilitiesfor the first 2 digits = 90 .
If 5 is a factor of a number, it means the number is divisible by 5. For the ones digit of the number to be 5, the number must end in 5. Since there are 10 possible digits (0-9), and only one of those digits is 5, the probability of the ones digit being 5 is 1 out of 10, or 1/10.
Oh, dude, a 21-digit number is called a "21-digit number." I mean, it's not like they have a fancy name for every length of numbers, you know? Just count those digits and there you have it, a 21-digit number. Keep it simple, right?