Q: What is an even number that can be formed using each of the digits 0 1 and 3?

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236789

18 of them.

Each of the 3 digits in a number can be any one of the four allowed.Total number of possibilities = (4 x 4 x 4) = 64numbers.

75431

501396

Related questions

236789

18 of them.

501396

256

Assuming each of the given digits can be used only once, the answer is 24. If not, the answer is infinity.

Each of the 3 digits in a number can be any one of the four allowed.Total number of possibilities = (4 x 4 x 4) = 64numbers.

75431

3

501396

396510

103596

965301