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Oh honey, that's an easy one. 9999999 in Roman numerals is written as IXCMXCIX. Just a bunch of I's, X's, C's, and M's all squished together. Roman numerals may look like a bunch of gibberish, but hey, it's all just fancy counting in the end.
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
If c were 3, the answer would be 30. If c were 5, the answer would be 130. c3+c1 = (c*c*c) + c
b+b+b+c+c+c+c =3b+4c
c^2 + c - 56 = (c - 7)(c + 8) using the factoring rule: c -7 -7c x x + c 8 8c c^2 -56 c
./c,c,c,c,c,c,c,c,c,c,c,c,c,c,c,c,c,c,c,
I only know the chorus but here it goes...... C C C C C C D C Bb D C Bb D Eb D C C C C C C C C C Bb C C C Bb D Bb Bb C D C C C C C C D C Bb D C Bb F F D C C C C C C C C C Bb C C C D Bb Bb A G I hope this helps you! ;)
Oh honey, that's an easy one. 9999999 in Roman numerals is written as IXCMXCIX. Just a bunch of I's, X's, C's, and M's all squished together. Roman numerals may look like a bunch of gibberish, but hey, it's all just fancy counting in the end.
These are the basic notes: C-C-C-C-C C-C-C-C-C C-C-C-C-B-C-D-E-G-A E-E-E-E-G-A-C-D-C-A-C-D-C-A
4 c.
c + c + c + c + c = 5 * c.
Seven Seas
c c c c b c c b c d e d c c c c b c c g(lower) c c c c b c c g (lower) c d g (lower) g higher) f e d e f e d c b c b b c d e d
C C D C A F A C D D C A G C C C C D C A G F A C D D D C C A G C F Bb Bb D C D D A G G BbA C C F A C C D C A F A C D D D C A A G C F. (:
pirates
c--c=c--c--c--c--c--c ............| ........c--c--c ............| ............c Don't worry about the dots, they're just there to get the methyl group to line up.
c + c + 2c + c + c = 6c