A number is divisible by 115 if it is divisible by both 5 and 23, as 115 = 5 * 23. To determine if a number is divisible by 5, you check if its last digit is 0 or 5. To check if a number is divisible by 23, you can use the divisibility rule for 23, which involves subtracting four times the last digit from the rest of the number and checking if the result is divisible by 23.
To find out what whole numbers can be divided by 115, first find the multiples.
115 x 2 = 230
115 x 3 = 345
115 x 4 = 460
etc..
All the results are multiples of 115. In this case 230, 345, and 460 are all divisible by 115.
Any multiple of 115, which is what you get when you multiply 115 by a whole number.
1, 2, 4, 5, 10, 20, 23, 46, 92, 115, 230, 460
If the number is x then 135*x = 115 so tat x = 115/135 = 0.851851...
115 = 5 × 23
The factors of 115 are 1, 5, 23, 115 For them to be common, they need to be compared to another set of factors.
2 is not divisible by 19008. 19008 is divisible by 2.
Yes, 5 × 23 = 115
Here 80 is less than 115.which is dividend is less than divisor.80 cant be divisible by 115. quotient will come in decimals.our question is nearest no to 80 divisible by 115.so starting first number in 115 multiplication table is 115. so 115 is the answer.
No, it is not.
230 divided by 115 is 2.
Not evenly.
115 ends in 5 which means it is divisible by 5. That makes it composite.
yes but not evenly its 11.5
Not evenly. It would give 57.5 as the answer.
345 is divisible by: 1 3 5 15 23 69 115 and 345.
115 is clearly prime since it ends in 5, therefore making it divisible by 5 and composite.
No. Is is divisible by 1, 5, 23, and itself. A prime number is divisible by only 1 and itself.
The number is 115.