To find what is divisible by 19, 57, and 38, we need to find the least common multiple (LCM) of these numbers. The LCM of 19, 57, and 38 is the smallest number that is divisible by all three numbers. To calculate the LCM, we can factorize each number into its prime factors: 19 = 19, 57 = 3 x 19, and 38 = 2 x 19. The LCM of 19, 57, and 38 is then the product of the highest power of each prime factor - in this case, 2 x 3 x 19 = 114. Therefore, 114 is divisible by 19, 57, and 38.
GCF(95, 38, 57) = 19.
The greatest common factor of 38 and 57 is 19. The prime factorization of 38 is 2*19 The prime factorization of 57 is 3*19 So the GCF is 19.
The GCF is 19.
19, 38, 57, 76, 95, 114, 133, 152, 171, 190, 209, 228, 247, 266, 285, 304, 323, 342, 361, 380.
19, 38, 57, 76, 95.
114 is divisible by: 1, 2, 3, 6, 19, 38, 57, 114
57 = 3 x 19 so 57 is divisible by 1, 3, 19 and 57.
GCF(95, 38, 57) = 19.
38 is divisible by 1, 2, 19, 38.
38 + 19 = 57.
There are an infinite series of numbers that are divisible by 228. Two of them are 456 and 684.On the other hand, if the questioner had meant "what is 228 divisible by?", then the answer is 2, 3, and 19, of which 2 applies twice.1, 2, 3, 4, 6, 12, 19, 38, 57, 76, 114, 228
1, 3, 19, 57.
The number that goes into both 38 and 57 is 19. This is because 38 divided by 19 equals 2, and 57 divided by 19 equals 3. In other words, 19 is a common factor of both 38 and 57.
The greatest common factor of 38 and 57 is 19. The prime factorization of 38 is 2*19 The prime factorization of 57 is 3*19 So the GCF is 19.
The GCF is 19.
No. it is composite. 57 is divisible by 3 and 19 :)
57 is divisible by 1, 3, 19 and 57.