0.8333
j/5
j/5
Power is work divided by time. 10 J in 5 s means the machine develops 2 watts of power.
2j+1/j+5 = 1 Multiply all terms by j+5 to eliminate the fraction: 2j+1 = j+5 2j-j = 5-1 j = 4
5+j=6. Now there is
bubblesort(int[] unsortedList){ 1)for(int i=1; ij=6 1 3 4 5 6 7 return 1 3 4 5 6 7 bubblesort(int[] unsortedList){ 1)for(int i=1; ij=6 1 3 4 5 6 7 return 1 3 4 5 6 7
The power output can be calculated as the work done divided by the time taken, so P = W/t. Plugging in the values: P = 200 J / 40 s = 5 watts. Therefore, the power output is 5 watts.
Lon J Fiala is 6' 5".
(j^3 + 3k^4)(j^6 - 3j^3k^4 + 9k^8)
Power = (energy used) / (time to use that much energy) = 40/5 = 8 watts
In the Mix - 1991 J Law 5-6 was released on: USA: 9 February 2012
Efficiency=Useful energy output divided by the energy input. i.e. 100 J is the energy input and you get 5 J light energy from a lamp, the waste energy would be 5 J.