In order to find a line that is perpendicular to y = 6x - 2, you need to take the negative reciprocal of the gradient.
The gradient of this graph is 6 as you know that all straight line graphs are in the form y = mx + c where m is the number in front of x and stands for gradient.
So, we take the negative reciprocal of 6.
If you take the reciprocal of 6, it is 1/6
If you then take the negative of it, it is -1/6
This -1/6 is the gradient of the line that will be perpendicular to the line y = 6x -2.
Therefore the line that will be perpendicular to it will be y = -1/6x + c where c can be any number.
Hope that helps.
Jamz159
6x + 2 = 6 6x = 4 x = 2/3
6x+7 = -56x = -12x = -2
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
9x + 3 - 6x - 2 = 3x + 1
If you mean: y = 6x+2 then its perpendicular line is -1/6.
6x+3y = -9 3y = -6x-9 y = -2x-3 Therefore the perpendicular slope is 1/2
7x + 2 = 6x + 2 if and only x = 0.
6x + 2 = 6 6x = 4 x = 2/3
6x+7 = -56x = -12x = -2
The quadratic expression x2+6x+8 when factorised equals (x+2)(x+4)
9x + 3 - 6x - 2 = 3x + 1
If you mean: y = 6x+2 then its perpendicular line is -1/6.
6x + 3 = 2x + 5 4x = 2 x=1/2
x=-6,5
20
1/6
(2, 1)