i dont know so you divied the
So, to put your question in an algebraic expression, it should look something like this: X/2 = 2X - 3 Then you would just solve... X = 2(2X - 3) X = 4X - 6 -3X = -6 X = 2
810: quotient 1, remainder 1
no, it simply multiplies the quotient by 1 (the multiplicative identity).
The answer is always positive. If the signs are the same (positive by positive, negative by negative), then the quotient is always positive. If the signs are different (positive by negative, negative by positive), then the quotient is always negative.
The quotient of a number and 2 is the same as the difference of the number doubled and 3.
The quotient is doubled. 8/4 = 2 8/2 = 4
9X-X/6
i dont know so you divied the
So, to put your question in an algebraic expression, it should look something like this: X/2 = 2X - 3 Then you would just solve... X = 2(2X - 3) X = 4X - 6 -3X = -6 X = 2
The number 1. Unless the number is 0, in which case, the quotient is not defined.
As long as the number is not zero, the quotient remains unchanged. If the multiplier is zero then the quotient is undefined.
When an integer is divided by 1 same integer number will be the quotient
810: quotient 1, remainder 1
No. Let's say you have 500 divided by 2. Your quotient would be 250.
no, it simply multiplies the quotient by 1 (the multiplicative identity).
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